Improve this answer. (Quarter 4, 2006 - Quarter 2, 2005 = 6) DP_MONTH returns the distance between the months capturing the input dates. You may need to change date format to match the a given date format and verify that 31 day months work for your specific scenarios. SELECT DISTINCT Test, FIRST_VALUE (CONVERT(DATE, datetime)) OVER (ORDER BY datetime DESC) StartDate,. Getting the months and years between two dates using Datediff There is a round up issue with the Datediff function. 3. AT TIME ZONE. Follow. MySQL DATEDIFF: Calculating weeks, months, or years between two dates. 2258064516 DATE_DIFF = 1. DATEENTERED between dateadd (mm, datediff (mm, 0, dateadd (MM, -1, getdate ())), 0) and dateadd (ms, -3, dateadd (mm,. The datediff function returns the difference between two specified dates in the time units that you specify: years, quarters, months, weeks, days, hours, minutes, or seconds. Answer: Oracle supports date arithmetic and you can make expressions like "date1 - date2" using date subtraction to get the difference between the two dates. 000000 1. You can even find the number of hours, minutes, seconds, and so on in terms of details in. SELECT purch_id, (trunc (sysdate, 'YYYY') + interval '11' month + interval '24' day) - purch_date days_to_christmas FROM CS260USER. The interval of time to use to calculate the difference between date1 and date2. DATEDIFF. 0. The function will always return the difference between two dates in days. Javascript. You can simply subtract two dates. What this allows you to do is pass in two TIMESTAMP or DATETIME values (or even DATE as MySQL will auto-convert) as well as the unit of time you want to base your difference on. . SELECT DATEADD (month, 1, '20220730'); The below DATEADD will add 1 year to the provided date value, the year changed from 2022 to 2023. g. TIMESTAMP Functions. Difference of two dates in months. Notice that the first row has a difference of 1. 9. You can write the query in a SQL statement using the DATEADD and DATEDIFF() function. The first one involves getting the difference in days and then converting it to 'x year y month z days'. That is, this function returns the count (as a signed integer value) of the specified datepart boundaries crossed between the specified start date and end date. Factor by 24 to get hours, 24*60 to get minutes, 24*60*60 to get seconds (that's as small as dates go). Taking out our calculator, we see that 30 minutes equals 1day/24hours*0. 構文 @DATEDIFF (' difference ', ' date ', ' date ') difference. Syntax:This expression: to_date(SYSDATE, 'yyyy-MM-dd') doesn't make sense. (Oct 2006 - June 2005 = 16) DP_WEEK returns the distance between the weeks capturing the input. Use DATEADD (): where HireDate < dateadd (year, -3, GETDATE ()) DATEDIFF () does not do what you think it does. Click Add Step to convert your column to a DateTime field. startdate or. The first day of the year is 1. For the last row return the calculated date. I didn’t know you answered questions including MySQL and. 65. Getting the months and years between two dates using Datediff There is a round up issue with the Datediff function. Declare @startdate datetime = '2013-11-01', @enddate datetime = '2013-11-11' SELECT (DATEDIFF (dd, @StartDate, @EndDate) + 1) - (DATEDIFF (wk, @StartDate, @EndDate) * 2) -. , SYSDATE - pr. Simply i need to convert this: SELECT FLOOR(DATEDIFF(NOW(),`startdate`)/365. 33 shows the available functions for date/time value processing, with details appearing in the following subsections. We will be using the same employees table in order to demonstrate the intricacies of calculating the difference between two dates in terms of weeks, months, or years using MySQL’s DATEDIFF() function. In SQL, we can add or subtract days, months, or years to a date by using the DATEADD function. Get the difference between datetimes in years, months, and days down to seconds. About; Products. (Oct 2006 - June 2005 = 16) DP_WEEK returns the distance between the weeks capturing the input dates. Share. this will gives you the last 3 month date (from 1st of the month) WHERE date_column >= DATEADD (MONTH, DATEDIFF (MONTH, 0, GETDATE ()) - 3, 0) you have 3 date. Calculate the last date of the month is quite simple calculation -. This command prints the order date in the specified format. montant_annuel = NEW. @KanagaveluSugumar - An Oracle DATE always has a year, month, day, hour, minute, and second component. ) Startdate = 2014-04-03 enddate = 2013-04-03 Result should be 12 as OP said. SELECT FIRST_NAME, HIRE_DATE, SYSDATE, SYSDATE - HIRE_DATE. First you get the number of years from the birth date up to now. The default is date format 1. datediff isn't a function in Oracle. If the dates are really timestamps, then this is easy - subtract them and the result is a day to second interval. mysql> SELECT something FROM tbl_name-> WHERE DATE_SUB(CURDATE(),INTERVAL 30 DAY) <= date_col; The query also selects rows with dates that lie in the future. expression1: This is a datetime expression you’ll substract expression2 from. February 28 and March 31) can lead to unintuitive behavior; specifically, increasing the first date in the pair does not always increase the output value. This works, but it is a bit clumsy compared to the sql server function:To get the difference between two date columns we can use DATEDIFF function in SQL Server and in Oracle we can just subtract two columns as shown below . Here is my trigger: SET NEW. DATEDIFF is a common function in the SQL Server to find the number of days between two dates. Returns NULL if either of <date_1> or <date_2> is NULL. Would give you rows where date2 (the later date) is 60 to 90 days later than date1. 0 days. Converting Valid Character Strings to Dates, Times, or Timestamps. TASKUNIQUEID, PROJ_TASK. Oracle offers its own solution, although does not have the DATEDIFF function. For example. Asked 6 years, 5 months ago. You could also use the add_months function: AND s. If you want the "exact" (as far as floating point gets) average, use. Oracle Fusion Global Human Resources Cloud Service - Version 11. SQL Database Dates is a MUST for. Syntax¶ MONTHS. DATE_ADD () Add time values (intervals) to a date value. DP_MONTH returns the distance between the months capturing the input dates. DATE is the main – or rather, original – datatype used in Oracle for holding dates. Function. 構文 @DATEDIFF (' difference ', ' date ', ' date ') difference. Currently I am only returning 1. The schema is SYSIBM. date2 Syntax. I suggest to use "months_between" function because it takes leap years into account (months_between wants 2 dates as parameters): select months_between(sysdate, to_date('1994-08-13', 'YYYY-MM-DD'))/12 from dual; 26,4729751904122. Then use these rules to set the column values: Start date: for the first row, return the input date; otherwise return the first of the month; End date: get the month start for the next row and subtract one day from it. Dates are always a joy to work with in any programming language, SQL not excluded. sql. g. SELECT DATEADD(month, DATEDIFF(month, 0, @mydate), 0) AS StartOfMonth Share. Step 5: Change Sort column. StartDate, SYSDATE) you would use: MONTHS_BETWEEN (pr. 32 illustrates the behaviors of the basic arithmetic operators ( +, *, etc. This is the reason we cannot apply direct addition or subtraction on date. g. The following illustrates the syntax of the DATEPART. date_from, evnt. 21. The fact that the function returns an integer number of months both when the days of the month are the same (e. We are now using NHibernate to connect to different database base on where our software is installed. by: sandy | last post by: Hi, Using Java script I am trying to create code where when you place in the start date it automatically calculates 6 months for the experations date. . Oracle DATEDIFF函数在Oracle中的使用 在本文中，我们将介绍Oracle数据库中的DATEDIFF函数。 阅读更多：Oracle 教程 什么是DATEDIFF函数？ DATEDIFF函数用于计算两个日期之间的时间间隔。它可以在Oracle数据库中使用，并返回一个整数值，表示两个日期之间的差异。这对于计算两个日期之间的天数、小时数、分钟. . Viewed 14k times 2 I'm looking to get total number of days including the Start Date and End Date, some examples below:. MONTHS_BETWEEN = 1. So, this expression converts SYSDATE to a string, using whatever local settings are on your system. The dates do not have to be in the same format in the extract file, but the format of each must be supported. This previous question indicates that there is a date format in Oracle that would make your year 92 into 2092 (i. I have to change it to '18-JAN-02' to get those. Sorted by: 193. AVERAGES CTE shows how to apply AVG function to. But it only for the date not for the time so i will be glad to know how to unite the two int columns + and convert it to date type for time difference. The Days, Months, and Years parameters can be negative or positive. )? SELECT (TRUNC (SYSDATE+1) – SYSDATE) *24 *60 *60 AS NOS_OF_SECS_LEFT FROM DUAL; These are some most important SQL Date Functions Examples. To find the date difference in minutes from the given DateTime values, use the following steps: - First, find the “date_diff” in days and multiply it with “24”. Difference of two dates in months. The Oracle/PLSQL MONTHS_BETWEEN function returns the number of months between date1 and date2. 0 for the month differnce the standard sql is DATEDIFF, in this function you must pass 3 params, if you must calculate the difference from 2 columns, c1 and c2, you must do this query . Here's the code provided by Tom Kyte at. The DATEPART () function returns an integer value that represents a specified part of the date of a given date. DaysInMonth Returns the number of days in the specified month and year. getYear () * 12 + date1. I have a creation date column in the table. The second method uses an extract function to obtain the years, months, and days separately. SELECT DATEDIFF(day, '2018-03-13', GETDATE()) AS "Difference in days"; On that basis, let me explain the three arguments required in the DATEDIFF function syntax. If you enter a negative parameter, the system subtracts the specified days, months, or years. DateValue > DateAdd (day,-3,getdate ()) doing this in this way makes your. SS: 差異を秒数で計算します。. Getting the last 12 months from a specific date is easy and can be retrieved by the following command in SQL-server. Functions. SELECT DATEDIFF (second, '2019-12-31 23:59:59', '2020-01-01 00:00:00'); A value of 1 is returned because the boundary of seconds is crossed once. There are two methods to achieve this. Share. Use DATEADD and DATEDIFF() function together in SQL query. 3 Answers. current_time() returns the date and time on the database client side. You could, of course, write your own function and call that. Since the value does not equal an entire month the result is 0. What's the function in Oracle that would be the equivalent to DATEDIFF in the SQL Server? On Oracle, it is an arithmetic issue: Select DATE1. Here's an example. 1 Answer. 1 row created. FWIW, you don't need to use floor. DECLARE @date datetime2 = '2021-01-07 14:36:17. date_open END. SELECT DATEADD(MONTH, DATEDIFF(MONTH, 0, GETDATE()), 0) As First_Of_Current_Month , DateAdd(dd, -1, DateAdd(mm, DateDiff(mm, 0, GETDATE()) +1, 0)) As Last_Of_Current. dbeaver. edited May 15, 2013 at 7:42. Once you have the date difference, you can use simple. NEXT_QUARTERDatediff between dates, but exclude extra leap year day Forum – Learn more on SQLServerCentral. Anybody help what is the equivalent of Dateadd and Datediff in DBeaver or anybody can convert this code in DBeaver. buf 1 declare 2 total_days integer; 3 total_weeks integer; 4 remaining_days integer; 5 begin 6 total_days := date '2014-12-16' - date '2014-12-01'; 7 total. Apr 2, 2013 at 6:13. The difference between the specified dates. Date Part Flexibility: Years, months, days, hours, minutes, and seconds are among the date parts that are supported. It should have been DATEDIFF NOT DATEADD with respect to the WEEK parameter. @Bruno - If the data types are TIMESTAMP WITH TIME ZONE, the interval that results from subtracting the two should take care of any time zone/ daylight savings time conversion. Fractions are allowed; you can add 2. Modified 2 years, 6 months ago. 2. Click on any table field/column. So far I have this: SELECT evnt. 850". So subtracting a TIMESTAMP WITH TIME ZONE that is 5 am Eastern from a TIMESTAMP WITH TIME ZONE that is 2 am Pacific will result in an interval of 0. Exactly as you said, use LEAST and GREATEST: CREATE FUNCTION datediff (p_from timestamp, p_to timestamp) return varchar2 is v_from TIMESTAMP := LEAST (p_from, p_to); v_to TIMESTAMP := GREATEST (p_from, p_to); l_years PLS_INTEGER; l_from TIMESTAMP; l_interval interval day (3) to second. Few examples of DATEDIFF: DATEDIFF - Example 1 Here, in this example, datepart is "day": SELECT DATEDIFF(day,'2016-06-05','2016-08-05') AS DiffDate. The system always returns a positive number regardless of which date. you can check against last 90 days. There are many tricks to generate rows in Oracle Database. Modified 1 year, 3 months ago. And lastly: I would strongly recommend using the ISO-8601 date format YYYYMMDD (here:. In short. All I need is to find the diff of these kind of dates in. for oracle: months_between. lastModified and w. Therefore, if you’re looking for. Teams. Justin, the example which you gave, if that is the scenario I want the output as 1. user637544 Jun 1 2009 — edited Jun 1 2009. The month and the last day of the month are defined by the parameter NLS_CALENDAR. Instead, use the dateAdd function on todays date, and compare the database table column to the result of that single calculation. I wanted to make the year as text in date dimension. The SQL DATEDIFF() function is an in-built function in SQL that is used to return the difference (as a signed integer value) between two dates or times. CASE WHEN a. 2. . DATE_FORMAT () Format date as specified. For example, you might use DateDiff to calculate the number of days between two dates, or the number of weeks between today and the end of the year. For example, this function returns 1. date_from) = 1. Example 2. Table 9. for the month differnce the standard sql is DATEDIFF, in this function you must pass 3 params, if you must calculate the difference from 2 columns, c1 and c2, you must do this query SELECT DATEDIFF(month,c1 , c2) FROM T WHERE. This post has been answered by BluShadow on Nov 18 2010. The system calculates the number of complete months between given dates. date_to) * 2) - CASE WHEN DATEPART(DW, evnt. It’s a seven byte store of century, year, month, day and hour, minute and second. A) Get the difference in months of dates on the same day The following example returns a difference in months between two dates: July 01 2017 and January 01 2017: SELECT MONTHS_BETWEEN ( DATE '2017-07-01', DATE '2017-01-01' ) MONTH_DIFF FROM DUAL; Code language: SQL (Structured Query Language) (sql) The result is 6 months as shown below: SQL> with 2 test (start_date, end_date) as 3 (select date '2020-10-01', 4 date '2020-11-02' 5 from dual 6 ), 7 calendar as 8 (select start_date + level - 1 datum 9 from test 10 connect by level <= end_date - start_date + 1 11 ) 12 select to_char(datum, 'yyyy. Can Any one help me please. January 30, 2022 5:11 PM / SQL. 25) AS `years`, COUNT(FLOOR(DATEDIFF(NOW(),`startdate`)/365. For example, from 2/10 to 3/10 is considered one month, and from 2/10 to 3/15 is also considered one month. Learn how to use The SQL Server DATEDIFF() Function to return the difference between two dates. 365 / 365. This can have results that you are not expecting. Oracle GoldenGate add trandata errors. If this format has been used to. 1. PostgreSQL - Date Difference in Months. You could simply minus the years but quarters would be. 00. DATEDIFF (MONTH, DATEADD (DAY,-DAY (startDate)+1,startDate),DATEADD (DAY,-DAY (startDate)+1,endDate)) Share. Factor by 24 to get hours, 24*60 to get minutes, 24*60*60 to get seconds (that's as small as dates go). SQL DATEPART. For example, adding three months or 12 days to a starting date. SELECT date_part ('month',age ('2016-06-30', '2018-06-30')) The result of this query is 0. 0. maybe something like passing an "m" as one of the parameters. If either expression is a character or graphic string, it must not be a CLOB. (Oct 2006 - June 2005 = 16) DP_WEEK returns the distance between the weeks capturing the input dates. 3. メンバーの日. e. Hi tom, I want day, month, minute and years difference everyting in seconds. It means that the DATEPART function returns the number of times the boundary between two units is crossed. E. One way to get our “DateDiff” function to exclude holidays and weekends is to have a calendar table pre-populated with some or all the information you need, and then use that table to exclude the dates. A note on Databricks: Databricks additionally supports a separate DATEDIFF function that takes only two arguments: a start date and an end date. Get Value for Last Month. DECLARE @yourDate DATE = '20160229' select DATEADD (MONTH, DATEDIFF (MONTH, -1, @yourDate)-1, -1) Just a note: this does remove any time portion in the input date, which may or may not be desired. I am adding filter to OTBI report and want system to take first and last date of current month automatically. FromDate, r. Second option is wrong when start hours/minutes/seconds is less then end. Columns c ) n cross join (select cast ('2001-01-01' as date) firstdate) const. 00000 - "%s: invalid identifier&quo. subtract and give the difference in number of months. CODE = 'CONTACT_CLIENT' THEN a. 1 Answer. From the inputs you got there are 123 months between the date of 07/03/2011 to 24/3/2021. i need to find the difference of two dates as the number of months: find the last day of the month of both the dates. Assuming the columns are already dates, and the therefore the conversion to and from strings you are doing is pointless, and that the difference is always going to be less than a day, you could do: to_char (date '1970-01-01' + abs (stp. DATEDIFF SQL Server function. Example 1: Fetching Employees who Joined Between Certain Dates. What is elapsed time in DB? DB Time is the Oracle server process CPU consumption and all non-idle wait time. If you omit fmt, then date is rounded to the. Ecco una semplice funzione per calcolare la differenza tra due date. You may: count the number of 24h elapsed time: day+1 - day = 1 day = 24h. How can we. DateDiff compares the values of the column you specify to work out the difference, it doesn't compare both dates and give you an exact difference. 0. Try SELECT SYSTIMESTAMP + INTERVAL '5' MINUTE, SYSTIMESTAMP + 5 / 24 / 60 to convince yourself. 1. =DATEDIFF ("d", Fields!startDate. 11. Viewed 3k times 0 I have table called C_Order. I was following along with the toad workbook 101 video (Toad Data Point Workbook 101: The Ins and Outs) and really wanting to replicate the presenter's use of the date diff() function. Date 1: 10th March 2011. Connect and share knowledge within a single location that is structured and easy to search. 2323 days) multiply by 24 = hours, another 60 = minutes, another 60 = seconds. So, the weird number you see is the difference between the two dates. UPDATE Yes, he will get a 1 month difference even if it is only 1 day difference, but OP. dividing by 365. Conversion between time units is also allowed; you can add, subtract, or compare dates by using days and state. The syntax for the DATEDIFF function in SQL Server (Transact-SQL) is: DATEDIFF( interval, date1, date2 ) Parameters or Arguments interval. The syntax for the DATEDIFF function is as follows:. g. Of course, if you need days instead of months, you can simply subtract one date from another, e. Label the column Years worked. QUARTER: returns the quarter of the date. Syntax The syntax for the MONTHS_BETWEEN function in Oracle/PLSQL is: MONTHS_BETWEEN ( date1, date2 ) Parameters or Arguments date1 The first date used to calculate the number of months between. This post has been answered by BluShadow on Nov 18 2010. create table test_table ( customer_num NUMBER, card_number char(2), card_issue_date DATE, card_expire_date DATE ). Tdy. In Oracle SQL, I want to display the difference between two dates in the format 'x years y months z days'. 997268. 2425. Modified 9 years, 7 months ago. 25) This seems to be another common approach - and was also given in a comment on my question. DATEDIFF_BIG () is a SQL function that was introduced in SQL Server 2016. Finally, we will use a CASE statement. For a baby born 28-Feb-17, properly calculated they turn 1 years old on 28-Feb-18 - their next birthday. SYSTIMESTAMP). Enter a date format string that describes the Date2 parameter. SELECT DATEDIFF (month,'2011-03-07' , '2021-06-24'); In this above example, you can find the number of months between the date of starting and ending. My DOB- 02-feb-1984 so my age should get as 27 Years 2 months 8 days How to do it. HQL Date format in Oracle / PostgreSQL: select TO_CHAR. 18. What I am using is (Today-Dob)/30/12, but this is not accurate as some months have 31 days. Oracle Oracle Database Release 19 SQL Language Reference MONTHS_BETWEEN Syntax Description of the illustration months_between. Try SELECT SYSTIMESTAMP + INTERVAL '5' MINUTE, SYSTIMESTAMP + 5 / 24 / 60 to convince yourself. date1. Converting a raw number of days into a number of weeks and days is pretty simple. 997268 (0 year + 365/366 years) So, in summary, the output (in DECIMAL (7,6)) from the above two examples would be: 1. Viewed 32k times. @WernfriedDomscheit YYYY-MM-DD is not a date it is just a formatted string. I have an application which calculates age on the specific date completely that is in years-months-days . Oracle offers its own solution, although does not have the DATEDIFF function. Expressions that return a value of any of the following built-in data types: a date, a timestamp, a character string, or a graphic string. In MS SQL Server, the DATEDIFF function is used to get the difference between two dates in terms of years, months, days, hours, minutes etc. Using datediff in oracle. ReturnDate) AS nvarchar(max)) END) AS [Duration] As a side note: I used nvarchar(max) for consistency with the first part of your query. Compare dates problems. DAYS function. This field level rule lets you display the difference between two dates. Sorted by: 3. Get the number of months between two dates. 2188940092 Example 2 Date 1: 10th March 2011 Date 2: 1st Feb 2011 MONTHS_BETWEEN = 1. Delaying Execution. SELECT DATEDIFF (YY, DateOfBirth, GETDATE ()) - CASE WHEN RIGHT (CONVERT (VARCHAR (6), GETDATE (), 12), 4) >= RIGHT (CONVERT (VARCHAR (6), DateOfBirth, 12), 4) THEN 0 ELSE 1 END AS AGE. What's the function in Oracle that would be the equivalent to DATEDIFF in the SQL Server? On Oracle, it is an arithmetic issue: Select DATE1-DATE2 from dual Converting a raw number of days into a number of weeks and days is pretty simple. I was given code via an SR but it doesn't work (I'm able to save the code but when I try to look at the sample data, it just says "error"). DateAdd. Value, Fields!endDate. The DATEDIFF() function returns the difference between two dates. Also, according to Oracle's documentation LAST_DAY returns a DATE. 092000000 AM format. lastModified and w. Value)/30. Funciones comúnmente utilizadas de Oracle: DateDiff devuelve una función personalizada para el intervalo entre dos fechas (Por supuesto, hay otros métodos para lograr, en ORACLE los tipos de fechas se pueden comparar directamente, y finalmente dar ejemplos de métodos). This function adds a number (a signed integer) to a datepart of an input date, and returns a modified date/time value. FLOOR (DATEDIFF (DAY, date_of_birth, reference_date) / 365. In Oracle, MONTHS_BETWEEN(date1, date2) function returns the number of months between two dates as a decimal number. The system always returns a positive number regardless of. It has been tested on a wide range of years (including leap ones) and more than 700k combinations of dates (including end of every months). sql. 6. Also to note that: DATEDIFF. Two dates to calculate the number of days between. Taking example 1, Oracle is telling me that 3rd Feb was a longer time ago than Informatica is telling me it is. To get the months or years separately, use extract. to get the date one second before midnight of. The function supports units of years, quarters, months, weeks, days, hours, minutes, seconds, milliseconds, microseconds, and nanoseconds. How to calculate years of experience from date_of_hiring to till date in months of an employee using sql query. select sysdate - date '2022-01-03' as delta from dual; The resulting value on the day I am running this is 37. So, i need to unite them to one column to check if the time difference is lower the 5. I want something like this. Examples. montant / (datediff (NEW. My Oracle Support provides customers with access to over a million knowledge articles and a vibrant support community of peers and Oracle experts. The number you’re left with is the number of days between the two days. 1. January=1, February=2, etc. SELECT DATEDIFF (second, '2019-12-31 23:59:59', '2020-01-01 00:00:00'); A value of 1 is returned because the boundary of seconds is. In Oracle, dates are just numbers. DP_MONTHは、入力日付をキャプチャする月の間隔を返します。(2006年10月- 2005年6月= 16)CONCAT((DATEDIFF(Minute,StartDate,EndDate)/60),':', (DATEDIFF(Minute,StartDate,EndDate)%60)) TimeTaken , and instead of calculating time difference once again using datediff if I can use the time taken value column which is already calculated the query execution will be faster. 3 Answers. DateGroup. Here is a PostgreSQL function with the exact same behavior as the Oracle MONTHS_BETWEEN function. - Find the “date_diff” in hours and multiply it by “60”. Order your results by the number of years employed. DateDiff. Learn more about TeamsPostgreSQL - Date Difference in Months. Sorted by: 55. Oracle also has the TO_CHAR function, so it allows TO_CHAR(whn, 'yyyymm'), for example. 取得一季中的第一天：. Select DATEDIFF (MM,0,GETDATE ()) Output - 1374, If getdate () output is "2014-07-23 19:33:46. Assuming that a. Asked 11 years, 5 months ago. Use the DATEDIF function when you want to calculate the difference between two dates. 0 months apart:Asked 3 years, 4 months ago. Can be one of the following values:1 Answer. DaysInYear Returns the number of days in the specified year. Its answer is 2014-08-17. Viewed 20k times. date_from, evnt. Syntax DATEDIFF (datepart ,startdate ,enddate) datepart Abbreviations year. 2 -Increment by 1 into total months count -. i need to find the difference of two dates as the number of months: find the last day of the month of both the dates. DATE () Extract the date part of a date or datetime expression. For each employee hired before 1992, display the employee’s last name, hire date and calculate the number of YEARS between TODAY and the date the employee was hired. I am looking for solution how to select number of days between two dates without weekends and public holidays. For example, this function returns 1.